How do you find the product (3c+6d)^2(3c+6d)2?

1 Answer
Feb 1, 2017

See the entire solution process below:

Explanation:

We can rewrite this expression as:

(3x + 6d)(3x + 6d)(3x+6d)(3x+6d)

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(color(red)(3c) + color(red)(6d))(color(blue)(3c) + color(blue)(6d))(3c+6d)(3c+6d) becomes:

(color(red)(3c) xx color(blue)(3c)) + (color(red)(3c) xx color(blue)(6d)) + (color(red)(6d) xx color(blue)(3c)) + (color(red)(6d) xx color(blue)(6d))(3c×3c)+(3c×6d)+(6d×3c)+(6d×6d)

9c^2 + 18cd + 18cd + 36d^29c2+18cd+18cd+36d2

We can now combine like terms:
9c^2 + (18 + 18)cd + 36d^29c2+(18+18)cd+36d2

9c^2 + 36cd + 36d^29c2+36cd+36d2