How do you find the product $(3t+12)(3t-12)$ ?

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Answer 1 · 2017-05-20T13:03:33

See a solution process below:

This is a special form:

$(a + b)(a - b) = a^2 - b^2$

Substituting $3t$ for $a$ and $12$ for $b$ gives:

$(3t + 12)(3t - 12) => (3t)^2 - 12^2 => 9t^2 - 144$

How do you find the product (3t+12)(3t-12)(3t+12)(3t-12)?