How do you find the product $(5 + x^{2} - 2 x) (2 x - 3)$ $(5 + x^2 - 2x) (2x - 3)$ ?

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How do you find the product $(5 + x^{2} - 2 x) (2 x - 3)$ $(5 + x^2 - 2x) (2x - 3)$ ?

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Answer 1 · 2015-05-18T14:59:26

You just multiply first one element by all the elements in the other factor, then proceed the same way.

For example, let's just rearrange it as $(2 x - 3) (5 + x^{2} - 3 x)$ $(2x-3)(5+x^2-3x)$

First, we multiply $2 x$ $2x$ by all the $(5 + x^{2} - 3 x)$ $(5+x^2-3x)$ factor, and then we do the same for $- 3$ $-3$ .

So,
$2 x (5 + x^{2} - 2 x) = 10 x + 2 x^{3} - 4 x^{2})$ $2x(5+x^2-2x)=10x+2x^3-4x^2)$
$- 3 (5 + x^{2} - 2 x) = - 15 - 3 x^{2} + 6 x$ $-3(5+x^2-2x)=-15-3x^2+6x$

Now, we just sum these results up, combining those elements with the same exponent in the variable $x$ $x$ .

Final answer: $2 x^{3} - 7 x^{2} + 16 x - 15$ $2x^3-7x^2+16x-15$

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How do you find the product $(5 + x^{2} - 2 x) (2 x - 3)$ $(5 + x^2 - 2x) (2x - 3)$ ?

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How do you find the product (5 + x^2 - 2x) (2x - 3)(5+x2−2x)(2x−3)(5 + x^2 - 2x) (2x - 3)?

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How do you find the product $(5 + x^{2} - 2 x) (2 x - 3)$ $(5 + x^2 - 2x) (2x - 3)$ ?