How do you find the product ${(5 t - 2)}^{2}$ $(5t-2)^2$ ?

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Answer 1 · 2017-02-04T12:33:48

$25 t^{2} - 20 t + 4$ $25t^2-20t+4$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $5 t - 2$ $5t-2$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $- - -$ $---$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $25 t^{2} - 10 t + 4$ $25t^2-10t+4$

$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $- 10 t$ $-10t$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $- - - - - -$ $------$

$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $25 t^{2} - 20 t + 4$ $25t^2-20t+4$

How do you find the product (5t-2)^2(5t−2)2(5t-2)^2?