How do you find the product $(6 z^{2} - 5 z - 2) (3 z^{3} - 2 z - 4)$ $(6z^2-5z-2)(3z^3-2z-4)$ ?

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Answer 1 · 2017-04-15T04:27:12

$18 z^{5} - 18 z^{3} - 29 z^{2} + 24 z + 8$ $18z^5-18z^3-29z^2+24z+8$

Given -

$(6 z^{2} - 5 z - 2) (3 z^{3} - 2 z - 4)$ $(6z^2-5z-2)(3z^3-2z-4)$

Multiply each term in the expression $(6 z^{2} - 5 z - 2)$ $(6z^2-5z-2)$ with $3 z^{3}$ $3z^3$

$18 z^{5} - 15 z^{2} - 6 z^{3}$ $18z^5-15z^2-6z^3$

Multiply each term in the expression $(6 z^{2} - 5 z - 2)$ $(6z^2-5z-2)$ with $- 2 z$ $-2z$

$18 z^{5} - 15 z^{2} - 6 z^{3} - 12 z^{3} + 10 z^{2} + 4 z$ $18z^5-15z^2-6z^3-12z^3+10z^2+4z$

Multiply each term in the expression $(6 z^{2} - 5 z - 2)$ $(6z^2-5z-2)$ with $- 4$ $-4$

$18 z^{5} - 15 z^{2} - 6 z^{3} - 12 z^{3} + 10 z^{2} + 4 z - 24 z^{2} + 20 z + 8$ $18z^5-15z^2-6z^3-12z^3+10z^2+4z-24z^2+20z+8$

Group all the like terms

$18 z^{5} - 6 z^{3} - 12 z^{3} - 15 z^{2} + 10 z^{2} - 24 z^{2} + 4 z + 20 z + 8$ $18z^5-6z^3-12z^3-15z^2+10z^2-24z^2+4z+20z+8$

Simplify

$18 z^{5} - 18 z^{3} - 29 z^{2} + 24 z + 8$ $18z^5-18z^3-29z^2+24z+8$

How do you find the product (6z^2-5z-2)(3z^3-2z-4)(6z2−5z−2)(3z3−2z−4)(6z^2-5z-2)(3z^3-2z-4)?