How do you find the product (b+8)(b+2)(b+8)(b+2)?

2 Answers
Apr 24, 2017

By multiplying, you can get b^2+10b+16b2+10b+16

Explanation:

Multiply all terms (b+8)(b+2)(b+8)(b+2)
b^2+2b+8b+16b2+2b+8b+16
Arrange this as:

b^2+10b+16b2+10b+16.

This is your answer.

Apr 24, 2017

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(color(red)(b) + color(red)(8))(color(blue)(b) + color(blue)(2))(b+8)(b+2) becomes:

(color(red)(b) xx color(blue)(b)) + (color(red)(b) xx color(blue)(2)) + (color(red)(8) xx color(blue)(b)) + (color(red)(8) xx color(blue)(2))(b×b)+(b×2)+(8×b)+(8×2)

b^2 + 2b + 8b + 16b2+2b+8b+16

We can now combine like terms:

b^2 + (2 + 8)b + 16b2+(2+8)b+16

b^2 + 10b + 16b2+10b+16