How do you find the product $(d + 4) (d + 10)$ $(d+4)(d+10)$ ?

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Answer 1 · 2017-05-03T09:25:56

$d^{2} + 14 d + 40$ $d^2+14d+40$

When you multiply terms in your equation, you will obtain:

$(d \cdot d) + (10 \cdot d) + (4 \cdot d) + (4 \cdot 10)$ $(d*d) + (10*d) + (4*d) + (4*10)$

or

$d^{2} + 14 d + 40$ $d^2 + 14 d + 40$

It is your answer:

$d^{2} + 14 d + 40$ $d^2 + 14d + 40$

If d=3, you will get $91$ $91$ from the aforegiven equation

From the original equation (on the question) $7 \cdot 13$ $7*13$ you will get the same result $91$ $91$

How do you find the product (d+4)(d+10)(d+4)(d+10)(d+4)(d+10)?