How do you find the product of (3d+3)(2d^2+5d-2)(3d+3)(2d2+5d2)?

1 Answer
Mar 25, 2017

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(color(red)(3d) + color(red)(3))(color(blue)(2d^2) + color(blue)(5d) - color(blue)(2))(3d+3)(2d2+5d2) becomes:

(color(red)(3d) xx color(blue)(2d^2)) + (color(red)(3d) xx color(blue)(5d)) - (color(red)(3d) xx color(blue)(2)) + (color(red)(3) xx color(blue)(2d^2)) + (color(red)(3) xx color(blue)(5d)) - (color(red)(3) xx color(blue)(2))(3d×2d2)+(3d×5d)(3d×2)+(3×2d2)+(3×5d)(3×2)

6d^3 + 15d^2 - 6d + 6d^2 + 15d - 66d3+15d26d+6d2+15d6

We can now group and combine like terms:

6d^3 + 15d^2 + 6d^2 - 6d + 15d - 66d3+15d2+6d26d+15d6

6d^3 + (15 + 6)d^2 + (-6 + 15)d - 66d3+(15+6)d2+(6+15)d6

6d^3 + 21d^2 + 9d - 66d3+21d2+9d6