How do you find the product of $(4h-2)(4h-1)$ ?

Question

2208 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-15T21:49:04

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(color(red)(4h) - color(red)(2))(color(blue)(4h) - color(blue)(1))$ becomes:

$(color(red)(4h) xx color(blue)(4h)) - (color(red)(4h) xx color(blue)(1)) - (color(red)(2) xx color(blue)(4h)) + (color(red)(2) xx color(blue)(1))$

$16h^2 - 4h - 8h + 2$

We can now combine like terms:

$16h^2 + (-4 - 8)h + 2$

$16h^2 + (-12)h + 2$

$16h^2 - 12h + 2$

How do you find the product of (4h-2)(4h-1)(4h-2)(4h-1)?