How do you find the product of $(4u+9v)^2$ ?

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Answer 1 · 2016-12-19T16:59:23

$16u^2+72uv+81v^2$

write as: $" "color(blue)((4u+9v))color(brown)((4u+9v))$

Multiply everything inside the right hand brackets by everything in the left hand brackets.

$color(brown)(color(blue)(4u)(4u+9v)color(blue)(" "+" "9v)(4u+9v) )$

$16u^2+36vu" "+" "36vu+81v^2$

$16u^2+72uv+81v^2$

How do you find the product of (4u+9v)^2(4u+9v)^2?