How do you find the product of $(6v+3)(6v-3)$ ?

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Answer 1 · 2016-06-29T12:15:14

$(6v+3)(6v-3)=36v^2-9$

We can use the identity $(a+b)(a-b)=a^2-b^2$

Here we have $(6v+3)(6v-3)$

= $(6v)^2-3^2$

= $36v^2-9$

Even if one intends to multiply

$(6v+3)(6v-3)$

= $6v(6v-3)+3(6v-3)$

= $(6v)^2-18v+18v-3^2$

= $36v^2-9$

How do you find the product of (6v+3)(6v-3)(6v+3)(6v-3)?