How do you find the product of $(b+3)(b+4)$ ?

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Answer 1 · 2017-03-07T23:28:20

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(color(red)(b) + color(red)(3))(color(blue)(b) + color(blue)(4))$ becomes:

$(color(red)(b) xx color(blue)(b)) + (color(red)(b) xx color(blue)(4)) + (color(red)(3) xx color(blue)(b)) + (color(red)(3) xx color(blue)(4))$

$b^2 + 4b + 3b + 12$

We can now combine like terms:

$b^2 + (4 + 3)b + 12$

$b^2 + 7b + 12$

How do you find the product of (b+3)(b+4)(b+3)(b+4)?