How do you find the product of $(h-2)(3h-5)$ ?

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Answer 1 · 2018-03-11T22:02:51

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(color(red)(h) - color(red)(2))(color(blue)(3h) - color(blue)(5))$ becomes:

$(color(red)(h) xx color(blue)(3h)) - (color(red)(h) xx color(blue)(5)) - (color(red)(2) xx color(blue)(3h)) + (color(red)(2) xx color(blue)(5))$

$3h^2 - 5h - 6h + 10$

We can now combine like terms:

$3h^2 + (-5 - 6)h + 10$

$3h^2 + (-11)h + 10$

$3h^2 - 11h + 10$

How do you find the product of (h-2)(3h-5)(h-2)(3h-5)?