How do you find the product of $(n-4)(n-6)$ ?

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Answer 1 · 2016-07-18T13:27:12

The product is $n^2 - 10n + 24$

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In order to multiply binomials we use the acronym FOIL

F - Firsts - Multiply the first terms
O - Outers - Multiply the outer terms
I - Inners - Multiply the Inner terms
L - Lasts - Multiply the Last terms

$(n)(n) + (n)(-6) + (-4)(n) + (-4)(-6)$

$n^2 - 6n -4n + 24$

Add like terms

$n^2 - 10n + 24$

Answer 2 · 2016-07-18T13:42:57

$n^2-10n+24$

Given: $" "color(blue)((n-4))color(brown)((n-6))$

Everything inside the brown bracket is multiplied by everything inside the blue bracket.

The 'minus' follows the blue 4

$color(brown)(color(blue)(n)(n-6)color(blue)(-4)(n-6) )$

$n^2-6n color(white)(...)-color(white)(...)4n+24$

$n^2-10n+24$

How do you find the product of (n-4)(n-6)(n-4)(n-6)?