How do you find the product of $(t+2)(t+9)$ ?

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Answer 1 · 2018-06-20T05:12:10

$t^2 + 11t + 18$

Here's how I did it:

$(t+2)(t+9)$

To simplify this, we will use the distributive method called FOIL:
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Following this image, we can multiply it out.

The $color(teal)("firsts")$ :
$color(teal)(t*t) = t^2$

The $color(indigo)("outers")$ :
$color(indigo)(t*9) = 9t$

The $color(peru)"inners"$ :
$color(peru)(2*t) = 2t$

The $color(olivedrab)"lasts"$ :
$color(olivedrab)(2*9) = 18$

Combine them all together to get your answer:
$t^2 + 9t + 2t + 18$

We can still combine the like terms $9t$ and $2t$ , so the final simplification is:
$t^2 + 11t + 18$

Hope this helps!

How do you find the product of (t+2)(t+9)(t+2)(t+9)?