How do you find the product of $(t+4)(t-3)$ ?

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Answer 1 · 2016-07-19T03:05:59

Use the distribution property.

In the destitution property each part of the parenthesis must be multiply by each part of the other parenthesis.

So multiply $t$ times $t$ and $t$ times $-3$ . This gives

$t * (t-3) = t^2 - 3t$

Then multiply $+4$ times $t$ and $+ 4$ times $-3$ . This gives

$4 * (t-3) = 4t -12$

Last add $4t$ and $-3t$ resulting $+t$ . The complete answer is

$t^2 + t -12$

How do you find the product of (t+4)(t-3)(t+4)(t-3)?