Question

How do you find the roots, real and imaginary, of `y=8x^2-2x -5` using the quadratic formula?

Answer 1

`color(orange)(x = (1 + sqrt31) / 8, (1 - sqrt31) / 8`

Explanation:

`y = 8x^2 - 2x - 5`

`a = 8, b = -2, c = -5`

`"quadratic formula is " x = (-b +- sqrt(b^2 - 4ac)) / (2a)`

`x = (2 +- sqrt(4 + 160)) / 16`

`x = (2 +- 2 sqrt31) / 16`

`color(orange)(x = (1 + sqrt31) / 8, (1 - sqrt31) / 8`