How do you find the value of $\frac{\sqrt{8}}{3 \sqrt{4}}$ $sqrt8 / (3sqrt4)$ in simplest form?

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Answer 1 · 2015-03-24T01:22:33

You can write:
$\frac{\sqrt{4 \cdot 2}}{3 \cdot 2} = \frac{2 \sqrt{2}}{3 \cdot 2} = \frac{\sqrt{2}}{3}$ $sqrt(4*2)/(3*2)=(2sqrt(2))/(3*2)=sqrt(2)/3$

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