How do you find the x and y intercept and slope of $y= - 6/5x + 6$ ?

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Answer 1 · 2015-07-10T22:38:56

The slope is $-6/5$ , the $y$ -intercept is at ( $0,6$ ), and the $x$ -intercept is at ( $5,0$ ).

The "slope-intercept" form of a straight line equation is

$y = mx + b$ ,

where $m$ is the slope and $b$ is the $y$ -intercept.

Your equation is

$y = -6/5x + 6$

If we compare the two equations, we see that

$m = -6/5$ and $b = 6$ .

So the slope is $-6/5$ and the $y$ -intercept is at ( $0,6$ ).

To get the $x$ -intercept, we set $y = 0$ and solve for $x$ ,

$y = -6/5x + 6$

$0 = -6/5x + 6$

$0 = -6x + 30$

$6x = 30$

$x = 30/6 = 5$

The $x$ -intercept is at ( $5,0$ ).

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How do you find the x and y intercept and slope of y= - 6/5x + 6y= - 6/5x + 6?