How do you find the x and y intercept for $2x+6y=-12$ ?

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Answer 1 · 2018-04-01T05:07:24

x- intercept $(-6,0)$
y-intercept $(0,-2)$

Given -

$2x+6y=-12$

To find the x-intercept put $y=0$

$2x+6(0)=-12$

$2x=-12$

$x=(-12)/2=-6$

x- intercept $(-6,0)$

To find the y-intercept put $x=0$

$2(0)+6y=-12$

$6y=-12$

$y=(-12)/6=-2$

y-intercept $(0,-2)$

How do you find the x and y intercept for 2x+6y=-122x+6y=-12?