How do you find the x and y intercept given $3x + 2y = 12$ ?

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Answer 1 · 2015-10-27T22:43:13

The x-intercept is at $(4,0)$
The y-intercept is at $(0,6)$

$3x+2y=12=>$ equation of a straight line in the standard form.

To find the x-intercept set y to zero then solve for x:
$3x+2*0=12$
$3x=12$
$x=4$
$:.$ the x-intercept is at $(4,0)$

To find the y-intercept set x to zero then solve for y:
$3*0+2y=12$
$2y=12$
$y=6$
$:.$ the y-intercept is at $(0,6)$

How do you find the x and y intercept given 3x + 2y = 123x + 2y = 12?