How do you find the x and y intercept of $3x+2y=6$ ?

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Answer 1 · 2017-04-05T12:59:59

$y_("intercept")=3 ->(x,y)=(0,3)$

$x_("intercept")=2->(x,y)=(2,0)$

Subtract $3x$ from both sides giving:

$2y=-3x+6$

Divide each side by 2

$y=-3/2 x+3$
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The y-intercept is at $x=0$ giving:

$y=-3/2(0)+3$

$y_("intercept")=3 ->(x,y)=(0,3)$
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The x-intercept is at $y=0$ giving:

$0=-3/2x+3$

$3/2x=3$

$x=2/3xx3 =2$

$x_("intercept")=2->(x,y)=(2,0)$

How do you find the x and y intercept of 3x+2y=63x+2y=6?