Question

How do you find the x and y intercept of `4x-3y+8=0`?

Answer 1

See the solution process below:

Explanation:

For the x-intercept:

Substitute `0` for `y` and solve for `x`:

`4x - 3y + 8 = 0` becomes:

`4x - (3 * 0) + 8 = 0`

`4x - 0 + 8 = 0`

`4x + 8 = 0`

`4x + 8 - color(red)(8) = 0 - color(red)(8)`

`4x + 0 = -8`

`4x = -8`

`(4x)/color(red)(4) = -8/color(red)(4)`

`(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = -2`

`x = -2`

The x-intercept is `-2` or `(-2, 0)`

For the y-intercept:

Substitute `0` for `x` and solve for `y`:

`4x - 3y + 8 = 0` becomes:

`(4 * 0) - 3y + 8 = 0`

`0 - 3y + 8 = 0`

`-3y + 8 = 0`

`-3y + 8 - color(red)(8) = 0 - color(red)(8)`

`-3y + 0 = -8`

`-3y = -8`

`(-3y)/color(red)(-3) = (-8)/color(red)(-3)`

`(color(red)(cancel(color(black)(-3)))y)/cancel(color(red)(-3)) = 8/3`

`y = 8/3`

The y-intercept is `8/3` or `(0, 8/3)`