How do you find the x and y intercept of $5x-3y=15$ ?

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Answer 1 · 2017-01-29T00:02:07

The $x-$ intercept is $(3,0)$
The $y-$ intercept is $(0,5)$

The $x$ and $y$ intercepts of of a linear equation can be found by plugging $0$ in for each variable and finding the solution for the other variable.

The $x$ - intercept is found where $y=0$
The $y$ - intercept is found where $x=0$

Solve for each independently.

$5x - 3y = 15$

$5x - 3(0) = 15$

$5x = 15$

$(cancel(5)x)/cancel5 = 15/5$

$x=3$

The $x-$ intercept is $(3,0)$

$5x - 3y = 15$

$5(0) - 3y = 15$

$3y = 15$

$(cancel(3)y)/cancel3 = 15/3$

$y=5$

The $y-$ intercept is $(0,5)$

How do you find the x and y intercept of 5x-3y=155x-3y=15?