Question

How do you find the x and y intercepts for `2x + 4y = -8`?

Answer 1

See explanation.

Explanation:

To find `x` interxept of a function you have to substitute `0` for `y` and solve the equation for `x`:

`2*x+4*0=-8`

`2x=-8`

`x=-4`

The `x` intercept is the point `(-4,0)`.

To find `y` intercept you have to substitute `0` for `x` and solve the equation for `y`:

`2*0+4*y=-8`

`4y=-8`

`y=-2`

The `y` intercept is the point `(0,-2)`.

Answer 2

x-intercept = `(-4,0)`
y-intercept = `(0,-2`)

Explanation:

x-intercept is when `y=0`
y-intercept is when `x=0`

Step 1:
Lets find the x-intercept by putting `y=0`

`2x+4y=-8`

`2x +(4 xx 0) = -8`

`2x +0 = -8`

`2x=-8`

`x= -8/2`

`x = -4` ------> x-intercept is `(-4,0)`

Step 2:
Lets find the y-intercept by putting `x=0`

`2x+4y=-8`

#(2 xx 0) +4y = -8

`0 + 4y = -8`

`4y=-8`

`y=-8/4`

`y = -2` -----> y-intercept is `(0,-2)`

if we plot the graph, we get the same.