How do you find the x and y intercepts for 2x+6y=122x+6y=12?

1 Answer
Mar 19, 2018

2x+6y=122x+6y=12

=> x+3y = 6x+3y=6

For x-intercept ,
plug in y=0y=0 and fin the value of xx
=> x +3(0) = 6x+3(0)=6
=> x=6x=6
Therefore the x-intercept is 6.

For y-intercept ,
plug in x=0x=0 and fin the value of yy
=> (0) +3y = 6(0)+3y=6
=> y=2y=2
Therefore the y-intercept is 2.

Alternatively, intercepts an also be found from the graph.
the points of intersection of the line representing x+2y=6x+2y=6 and the x-axis and y-axis represents the x-intercept graph and y-intercept respectively.

graph{x+3y=6 [-10, 10, -5, 5]}