How do you find the x and y intercepts for $3x – 2y = 15$ ?

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Answer 1 · 2018-03-02T02:58:43

The $y$ -intercept is $(0,-15/2)$ and the $x$ -intercept is (5,0).

Set one variable to zero and solve for the other.

Setting $x=0$ will give the $y$ -intercept:
$3(0)-2y=15$
$-2y=15$
$y = -15/2$

Setting $y=0$ will give the $x$ -intercept:
$3x-2(0)=15$
$3x=15$
$x=5$

Hence, the $y$ -intercept is $(0,-15/2)$ and the $x$ -intercept is (5,0).

How do you find the x and y intercepts for 3x – 2y = 153x – 2y = 15?