How do you find the x and y intercepts for f(x) = (x-3)^2 + 17?

1 Answer
Aug 2, 2017

"y-intercept "=26" no x-intercepts"

Explanation:

"to find the intercepts"

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercepts"

x=0toy=(-3)^2+17=26larrcolor(red)" y-intercept"

y=0to(x-3)^2+17=0

rArr(x-3)^2=-17

AAx inRRcolor(white)(x) (x-3)^2>=0

rArr" there are no x-intercepts"
graph{(x-3)^2+17 [-80, 80, -40, 40]}