How do you find the x and y intercepts for f(x) = (x-3)^2 + 17?
1 Answer
Aug 2, 2017
Explanation:
"to find the intercepts"
• " let x = 0, in the equation for y-intercept"
• " let y = 0, in the equation for x-intercepts"
x=0toy=(-3)^2+17=26larrcolor(red)" y-intercept"
y=0to(x-3)^2+17=0
rArr(x-3)^2=-17
AAx inRRcolor(white)(x) (x-3)^2>=0
rArr" there are no x-intercepts"
graph{(x-3)^2+17 [-80, 80, -40, 40]}