How do you find the x and y intercepts for y=2/3x-8?
1 Answer
Apr 29, 2018
Explanation:
"to find the intercepts, that is where the graph crosses"
"the x and y axes"
• " let x = 0, in the equation for y-intercept"
• " let y = 0, in the equation for x-intercept"
x=0rArry=0-8=-8larrcolor(red)"y-intercept"
y=0rArr2/3x-8=0
rArr2/3x=8rArrx=(8xx3)/2=12larrcolor(red)"x-intercept"
graph{(y-2/3x+8)((x-0)^2+(y+8)^2-0.04)((x-12)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}