How do you find the x and y intercepts for $y=-2x+5$ ?

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Answer 1 · 2016-03-29T16:29:20

$x_(" intercept")=5/2 ->(x,y)->(5/2,0)$

$y_(" intercept")=5->(x,y)->(0,5)$

$y$ intercept is when $x=0$

$x$ intercept is when $y=0$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$color(blue)("To find "x_("Intercept"))$

Set $y=0$ giving

$" "0=-2x+5$

Add $2x$ to both sides

$" "2x=-2x+2x+5$

$" "2x=0+5$

Divide both sides by 2

$" "2/2xx x=5/2$

But $2/2=1$

$" "color(blue)(x=5/2)$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$color(blue)("To find "y_("Intercept"))$

Set $x=0$

$" "y=-2(0)+5$

$" "color(blue)(y=5)$

How do you find the x and y intercepts for y=-2x+5y=-2x+5?