How do you find the x and y intercepts for y=3x-2?

2 Answers
Apr 12, 2018

y = -2
x = 0
(0,-2)

Explanation:

Add two to both sides.
y = 3x - 2
to
y + 2 = 3x

Next, instead of x, put y + 2.
y + 2= 3(y+2)

Then, multiply 3 by y and 3 by 2.
y +2= 3y + 6

Subtract y from both sides.
2 + y = 3y + 6
to
2 = 2y + 6

Subtract 6 from both sides.
2 = 2y + 6
to
-4 = 2y

Divide both sides by 2.
-4 = 2y
to
-2 = y
Go back to the original equation. Replace y with -2.
y = 3x - 2
to
-2 = 3x - 2

Add 2 to both sides.
-2 = 3x - 2
to
0 = 3x

Divide both sides by 3.
0 = 3x
to
0 = x

Hope that helped! : )

Apr 12, 2018

The x-intercept is (2/3,0).

The y-intercept is (0,-2).

Explanation:

Given:

y=3x-2

X-intercept: value of x when y=0.

Substitute 0 for y.

0=3x-2

Add 2 to both sides.

2=3x

Divide both sides by 3.

2/3=x

The x-intercept is (2/3,0).

Y-intercept: value of y when x=0

y=3x-2 is the slope-intercept form for a linear equation:

y=mx+b,

where:

m is the slope, and b is the y-intercept.

Therefore, the y-intercept is (0,-2).

You can also substitute 2 for x and solve for y.

y=3(0)-2

y=-2

The y-intercept is (0,-2).

graph{y=3x-2 [-10, 10, -5, 5]}