How do you find the x and y intercepts for $y = 3 x - 4$ $y= 3x-4$ ?

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Answer 1 · 2015-11-13T18:51:24

$x$ $x$ intercept: $(\frac{4}{3}, 0)$ $(4/3,0)$

$y$ $y$ intercept: $(0, - 4)$ $(0,-4)$

The $x$ $x$ intercept is the point of the line for which $y = 0$ $y=0$ , so

$0 = 3 x - 4 \to 3 x = 4 \to x = \frac{4}{3}$ $0=3x-4 -> 3x=4 -> x=4/3$

The $y$ $y$ intercept is the point of the line for which $x = 0$ $x=0$ , so

$y = 3 \cdot 0 - 4 = - 4$ $y=3*0-4 = -4$

How do you find the x and y intercepts for y= 3x-4y=3x−4y= 3x-4?