How do you find the x and y intercepts for $y= -5/3x+ 2$ ?

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Answer 1 · 2018-04-11T07:56:09

(0,2) and (3,0)

The intercepts are when the $x and y$ values are zero

$y=(-5)/3x+2$ when $x=0$ is $y=0+2$ , $y=2$

$y=(-5)/3x+2$ when $y=0$ is $0=(-2)/3x+2$

$=>$ $-2=(-2)/3x$ by subtracting 2 from each side

$=>$ $-6=-2x$ by multiplying both sides by 3

$=>$ $3=x$ by dividing both sides by -2

How do you find the x and y intercepts for y= -5/3x+ 2y= -5/3x+ 2?