How do you find the x and y intercepts of $1/2x+2y=-2$ ?

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Answer 1 · 2017-05-07T06:58:52

See a solution process below:

To find the x-intercept:

Substitute $0$ for $y$ and solve for $x$ :

$1/2x + 2y = -2$ becomes:

$1/2x + (2 * 0) = -2$

$1/2x + 0 = -2$

$1/2x = -2$

$color(red)(2) * 1/2x = color(red)(2) * -2$

$cancel(color(red)(2)) * 1/color(red)(cancel(color(black)(2)))x = -4$

$x = -4$

The x-intercept is $x =-4$ or $(-4, 0)$

To find the y-intercept:

Substitute $0$ for $x$ and solve for $y$ :

$1/2x + 2y = -2$ becomes:

$(1/2 * 0) + 2y = -2$

$0 + 2y = -2$

$2y = -2$

$(2y)/color(red)(2) = -2/color(red)(2)$

$(color(red)(cancel(color(black)(2)))y)/cancel(color(red)(2)) = -2/color(red)(2)$

$y = -1$

The y-intercept is $y =-1$ or $(0, -1)$

How do you find the x and y intercepts of 1/2x+2y=-21/2x+2y=-2?