Question

How do you find the x and y intercepts of `-4x=8y+12`?

Answer 1

x-intercept: `(-3, 0)`
y-intercept: `(0, -3/2)`

Explanation:

The x-intercept occurs when the line crosses the x-axis. If you think about it, this point occurs when `y=0`.

`-4x=8*0+12=12` {substituted `y=0`}
`x=-3`

When `y=0`, `x=-3`. The x-intercept is therefore `(-3, 0)`.

The y-intercept occurs when the line crosses the y-axis. As above, this point occurs when `x=0`.

`-4*0=8y+12` {substituted `x=0`}
`y=-12/8=-3/2`

When `x=0`, `y=-3/2`. The y-intercept is therefore `(0, -3/2)`.

Answer 2

`"y-intercept "=-3/2," x-intercept "=-3`

Explanation:

To find the `color(blue)"x and y intercepts"`

`• " let x = 0, in the equation, for y-intercept"`

`• " let y = 0, in the equation, for x-intercept"`

`x=0to8y+12=0to8y=-12toy=-3/2`

`y=0to-4x=0+12to-4x=12tox=-3`
graph{-1/2x-3/2 [-10, 10, -5, 5]}