How do you find the x and y intercepts of $-5x+10y=20$ ?

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Answer 1 · 2017-08-13T17:48:40

See a solution process below:

One way to find the $x$ and $y$ -intercepts is to set one variable equal to $0$ and solve for the other variable.

x-intercept:

Set $y = 0$ giving:

$-5x + (10 * 0) = 20$

$-5x + 0 = 20$

$-5x = 20$

$(-5x)/color(red)(-5) = 20/color(red)(-5)$

$(color(red)(cancel(color(black)(-5)))x)/cancel(color(red)(-5)) = -4$

$x = -4$

The $x$ -intercept is: $-4$ or $(-4, 0)$

y-intercept:

Set $x = 0$ giving:

$(-5 * 0) + 10y = 20$

$0 + 10y = 20$

$10y = 20$

$(10y)/color(red)(10) = 20/color(red)(10)$

$(color(red)(cancel(color(black)(10)))y)/cancel(color(red)(10)) = 2$

$y = 2$

The $y$ -intercept is: $2$ or $(0, 2)$

How do you find the x and y intercepts of -5x+10y=20-5x+10y=20?