How do you find the x and y intercepts of $5y=7.5-2.5x$ ?

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Answer 1 · 2016-09-09T14:18:05

$y_("intercept")=3/2$

$x_("intercept")=3$

Lets get rid of the decimals. Multiply both sides by 2

$2(5y)=2(7.5-2.5x)$

$10y=15-5x$

Divide both sides by 10

$y=15/10-5/10x$

$y=3/2-1/2x$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
y intercept is at $x=0$ so by substitution

$y_("intercept")" "=" "3/2-1/2(0)" "=" "3/2$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x intercept is at $y=0$ so by substitution

$0=3/2-1/2(x_("intercept"))$

$=> +1/2(x_("intercept"))=3/2$

$x_("intercept")=3$

Answer 2 · 2016-09-09T14:22:29

x intercept is 3
y intercept is 1.5

To find x intercept we should substitute $y$ by zero
To find y intercept we should substitute $x$ by zero

x intercept for the given equation:
$5(0)=7.5-2.5x$
$rArr 0= 7.5-2.5x$
$rArr 0=7.5-2.5x$
$rArr-7.5=-2.5x$
$rArrx=(-7.5)/-2.5$
$rArrx=3$

y intercept of the given equation:
$5y=7.5-2.5(0)$
$rArr5y=7.5-0$
$rArr5y=7.5$
$rArry=7.5/5$
$rArry=1.5$

Therefore, x intercept is 3 and y intercept is 1.5

How do you find the x and y intercepts of 5y=7.5-2.5x5y=7.5-2.5x?