How do you find the x and y intercepts of $6x+2y=10$ ?

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Answer 1 · 2016-11-07T13:31:55

The intercepts are at $(1 2/3, 0) and (0, 5)$

Leave the equation $6x +2y = 10$ in this form.

All along the $x-$ axis, $y=0" "$ All along the $y-$ axis, $x=0$

To find the $y-$ intercept, set $x=0$

$6(0) + 2y = 10" "rarr y = 5$

To find the $x-$ intercept, set $y=0$

$6x + 2(0) = 10" " rarr x = 10/6 = 5/3 = 1 2/3$

The intercepts are at $(1 2/3, 0) and (0, 5)$

How do you find the x and y intercepts of 6x+2y=106x+2y=10?