Question

How do you find the x and y intercepts of `8y-5=3x`?

Answer 1

See the entire solution process below:

Explanation:

To find the x-intercept we set `color(red)(y)` to `color(red)(0)` and solve for `x`:

`8color(red)(y) - 5 = 3x` becomes:

`(8 xx color(red)(0)) - 5 = 3x`

`0 - 5 = 3x`

`-5 = 3x`

`-5/color(red)(3) = (3x)/color(red)(3)`

`-5/3 = x`

`x = -5/3`

To find the y-intercept we set `color(red)(x)` to `color(red)(0)` and solve for `y`:

`8y - 5 = 3color(red)(x)` becomes:

`8y - 5 = (3 xx color(red)(0))`

`8y - 5 = 0`

`8y - 5 + color(red)(5) = 0 + color(red)(5)`

`8y - 0 = 5`

`(8y)/color(red)(8) = 5/color(red)(8)`

`(color(red)(cancel(color(black)(8)))y)/cancel(color(red)(8)) = 5/8`

`y = 5/8`

The x-intercept is `-5/3` or `(-5/3, 0)`

The y-intercept is `5/8` or `(0, 5/8)`