How do you find the x and y intercepts of $y=2/3x-4$ ?

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Answer 1 · 2017-03-01T15:24:21

See the entire solution process below:

To find the y-intercept by substitution, substitute $0$ for $x$ and calculate $y$ :

$y = (2/3 xx 0) - 4$

$y = 0 - 4$

$y = -4$ Therefore the y-intercept is $-4$ or $(0, -4)$

To find the x-intercept by substitution, substitute $0$ for $y$ and solve for $x$ :

$0 = 2/3x - 4$

$0 + color(red)(4) = 2/3x - 4 + color(red)(4)$

$4 = 2/3x - 0$

$4 = 2/3x$

$color(red)(3)/color(blue)(2) xx 4 = color(red)(3)/color(blue)(2) xx 2/3x$

$12/color(blue)(2) = cancel(color(red)(3))/cancel(color(blue)(2)) xx color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(3)))x$

$6 = x$

$x = 6$ Therefore the x-intercept is $6$ or $(6, 0)$

How do you find the x and y intercepts of y=2/3x-4y=2/3x-4?