How do you find the x and y intercepts of $y=-x+1$ ?

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Answer 1 · 2017-02-08T00:20:39

See the solution process below:

The slope-intercept form of a linear equation is: $y = color(red)(m)x + color(blue)(b)$

Where $color(red)(m)$ is the slope and $color(blue)(b)$ is the y-intercept value.

This equation is in the slope intercept form ( $y = color(red)(-1)x + color(blue)(1)$ )

The y-intercept is $color(blue)(b = 1)$ or $(0, 1)$

To find the x-intercept set $y$ to $0$ and solve for $x$ :

$0 = color(red)(-1)x + color(blue)(1)$

$0 - 1 = color(red)(-1)x + color(blue)(1) - 1$

$-1 = color(red)(-1)x + 0$

$-1 = color(red)(-1)x$

$color(blue)(-1) xx -1 = color(blue)(-1) xx color(red)(-1)x$

$1 = 1x$

$x = 1$

The x-intercept is $1$ or $(1, 0)$

How do you find the x and y intercepts of y=-x+1y=-x+1?