How do you find the y intercepts for $q (x) = - 7^{x - 4} - 1$ $q(x) = -7^(x-4) -1$ ?

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How do you find the y intercepts for $q (x) = - 7^{x - 4} - 1$ $q(x) = -7^(x-4) -1$ ?

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Answer 1 · 2015-06-15T13:26:41

The y -intercept is at $- (1 + \frac{1}{1401})$ $-(1+1/1401)$
(but see note below).

Explanation:

The y-intercept is where the function crosses the y-axis; for all points on the y-axis, $x = 0$ $x=0$ .

When $x = 0$ $x=0$
$XXXX$ $color(white)("XXXX")$ $g (x)$ $g(x)$ (also know as $y$ $y$ ) $= - 7^{x - 4} - 1$ $= -7^(x-4)-1$
$XXXX$ $color(white)("XXXX")$ becomes
$XXXX$ $color(white)("XXXX")$ $g (0) = - 7^{- 4} - 1$ $g(0) = -7^-4-1$
$XXXX$ $color(white)("XXXX")$ $XXXX$ $color(white)("XXXX")$ $= - \frac{1}{7^{4}} - 1$ $= - 1/(7^4) -1$ see note below
$XXXX$ $color(white)("XXXX")$ $XXXX$ $color(white)("XXXX")$ $= - (1 + \frac{1}{1401})$ $= -(1+1/1401)$

note
This assumes $- 7^{x - 4}$ $-7^(x-4)$ is interpreted as $- (7^{x^{4}})$ $-(7^(x^4))$ and not as $(- 7_{^} (x - 4))$ $(-7_^(x-4))$ . If this is not the case the correct answer would be $- (1 - \frac{1}{1401})$ $-(1-1/1401)$

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How do you find the y intercepts for $q (x) = - 7^{x - 4} - 1$ $q(x) = -7^(x-4) -1$ ?

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Explanation:

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How do you find the y intercepts for q(x) = -7^(x-4) -1q(x)=−7x−4−1q(x) = -7^(x-4) -1?

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Explanation:

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How do you find the y intercepts for $q (x) = - 7^{x - 4} - 1$ $q(x) = -7^(x-4) -1$ ?