How do you FOIL $(2 x + 3) (x - 2)$ $(2x + 3) (x-2)$ ?

Question

4833 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-23T01:19:19

$2 x^{2} - x - 6$ $2x^2-x-6$

The operation is called distribution, the acrynom to remember how to multiply 2 binomials is FOIL.

It's important to understand that 'foiling' something is a misnomer and should only be used as a guide for how to perform the operation.

Recall, FOIL stands for First - Outer - Inner - Last.

Begin by multiplying the first 2 terms. $2 x \cdot x = 2 x^{2}$ $2x*x = 2x^2$

Then, multiply the outer terms. $2 x \cdot - 2 = - 4 x$ $2x*-2 = -4x$ (Don't forget to take the negative that is attached to the 2).

Multiply the inner terms. $3 \cdot x = 3 x$ $3*x = 3x$

Lastly, multiply the last terms. $3 \cdot - 2 = - 6$ $3*-2=-6$

Then, write them all out in the order that you performed the operations.

$2 x^{2} - 4 x + 3 x - 6$ $2x^2-4x+3x-6$

Then, combine like terms.

$2 x^{2} - x - 6$ $2x^2-x-6$

How do you FOIL (2x + 3) (x-2)(2x+3)(x−2) (2x + 3) (x-2)?