How do you FOIL (3x^2-6)(x^3-9)(3x2−6)(x3−9)?

1 Answer
Meave60
May 31, 2015

(3x^2-6)(x^3-9)=3x^5-27x^2-6x^3+54(3x2−6)(x3−9)=3x5−27x2−6x3+54

Problem: FOIL (3x^2-6)(x^3-9)(3x2−6)(x3−9) .

FOIL stands for:

First: Multiply the first term in each binomial together.
Outer/Outside: Multiply the outer/outside term in each binomial together.
Inner/Inside: Multiply the inner/inside term in each binomial together.
Last: Multiply the last term in each binomial together.

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(3x^2-6)(x^3-9)(3x2−6)(x3−9) =

(3x^2*x^3)+(3x^2*-9)+(-6*x^3)+(-6*(-9))(3x2⋅x3)+(3x2⋅−9)+(−6⋅x3)+(−6⋅(−9)) =

3x^5-27x^2-6x^3+543x5−27x2−6x3+54

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