How do you FOIL $(\sqrt 5 + \sqrt 2) (\sqrt 5 - \sqrt 2)$ $(√5 + √2) (√5 - √2)$ ?

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How do you FOIL $(\sqrt 5 + \sqrt 2) (\sqrt 5 - \sqrt 2)$ $(√5 + √2) (√5 - √2)$ ?

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Answer 1 · 2015-06-21T17:00:19

$5 - 2 = 3$ $5-2=3$

Explanation:

$(\sqrt{5} + \sqrt{2}) (\sqrt{5} - \sqrt{2}) =$ $(sqrt(5)+sqrt(2))(sqrt(5)-sqrt(2))=$
$=(sqrt(5)sqrt(5))cancel(-(sqrt(5)sqrt(2)))+cancel((sqrt(2)sqrt(5)))-(sqrt(2)sqrt(2))=$
$=5-2=3$

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How do you FOIL $(\sqrt 5 + \sqrt 2) (\sqrt 5 - \sqrt 2)$ $(√5 + √2) (√5 - √2)$ ?

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How do you FOIL (√5 + √2) (√5 - √2)(√5+√2)(√5−√2)(√5 + √2) (√5 - √2)?

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