How do you FOIL $(7q + 2)(7q - 2)$ ?

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Answer 1 · 2015-05-29T21:19:37

First : $7q*7q$
Outside : $7q*(-2)$
Inside : $2*7q$
Last : $2*(-2)$

$(7q*7q)+7q*(-2)+2*7q+2*(-2)$

Multiply inside each term:

$49q^2-14q+14q-4$

Terms $-14q$ and $14q$ cancel out

$49q^2-4$

How do you FOIL (7q + 2)(7q - 2)(7q + 2)(7q - 2)?