How do you FOIL (s^2+t)(s^2-t)?

1 Answer
May 26, 2015

Given color(red)((s^2+t))color(blue)((s^2-t))

First terms: color(red)(s^2) and color(blue)(s^2)
Outside terms: color(red)(s^2) and color(blue)((-t))
Inside terms: color(red)(t) and color(blue)(s^2)
Last terms: color(red)(t) and color(blue)(-t)

The FOIL method is to
Sum

the product of the First terms (s^2xxs^2 = s^4)
the product of the Outside terms (s^2xx(-t) = (-s^2t))
the product of the Inside terms (t xx s^2 = s^2t)
and
the product of the Last terms (txx(-t) = (-t^2)

For the given example this sum is s^4-t^2