How do you FOIL (x+4)(x+1) ?

1 Answer
May 28, 2015

Given color(red)((x+4))color(blue)((x+1))

F irst terms: color(red)(x)xxcolor(blue)(x) = x^2
O utside terms: color(red)(x)xxcolor(blue)(1) = 1x
I nside terms: color(red)(4)xxcolor(red)(x) = 4x
L ast terms: color(red)(4)xxcolor(red)(1) = 4

Sum of FOIL =x^2+5x+4