How do you foil (x-8)(x+4)(x8)(x+4)?

1 Answer
Aug 6, 2015

x^2-4x-32x24x32

Explanation:

In FOIL, the "F" stands for "First" (times First), the "O" stands for "Outside" (times Outside), the "I" stands for "Inside" (times Inside), and the "L" stands for "Last" (times Last).

With the product (x-8)(x+4)(x8)(x+4) of the two binomials x-8x8 and x+4x+4, First-times-First gives x*x=x^2xx=x2, Outside-times-Outside gives x*4=4xx4=4x, Inside-times-Inside is -8*x=-8x8x=8x, and Last-times-Last is -8*4=-3284=32.

Hence, (x-8)(x+4)=x^2+4x-8x-32=x^2-4x-32(x8)(x+4)=x2+4x8x32=x24x32

The reasons the FOIL method works has to do with the distributive and commutative properties:

(a+b)*(c+d)=(a+b)*c+(a+b)*d(a+b)(c+d)=(a+b)c+(a+b)d

=a*c+b*c+a*d+b*d=ac+ad+bc+bd=ac+bc+ad+bd=ac+ad+bc+bd