How do you foil $(x + 8) (x - 8)$ $( x+8) (x - 8)$ ?

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Answer 1 · 2015-09-18T17:37:33

$= x^{2} - 64$ $=color(blue)(x^2-64$

The expression is : $(x + 8) (x - 8)$ $(x+8)(x-8)$

F O I L involves carrying out the below operations in the following order:

1) product of First terms : $(x and x)$ $(color(blue)(x and x))$ +

2)product of Outside terms: $(x and - 8)$ $(color(blue)(x and -8))$ +

3)product of Inside terms: $(8 and x)$ $(color(blue)(8 and x))$ +

4)product of Last terms: $(8 and - 8)$ $(color(blue)(8 and -8))$

1) $x \cdot x = x^{2} +$ $x *x=color(blue)(x^2) +$

2) $x \cdot - 8 = - 8 x +$ $x * -8=-color(blue)(8x)+$

3) $8 \cdot x = 8 x +$ $8 * x = color(blue)(8x)+$

4) $8 \cdot - 8 = - 64$ $8 *-8 = color(blue)(-64$

adding all the terms

$= x^{2} - 8 x + 8 x - 64$ $=color(blue)(x^2-8x +8x -64$
$= x^{2} - 64$ $=color(blue)(x^2-64$

How do you foil ( x+8) (x - 8)(x+8)(x−8)( x+8) (x - 8)?